Discard unwanted information from string array

Hello Everyone,

I am in need of a help to remove some part of information from the string array.

I have a 8x1 string array with the information shown below,

ans = 
  8×1 string array
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/20219.png" alt="Optimizing application documents">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/19987.png" alt="Gedächtnis- und Konzentrationstechniken">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/19973.png" alt="LiT.Workshop: Instruktionsvideos der eigenen Lehre erstellen">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/20003.png" alt="Flexible Arbeit im Kontext eines digitalen Unternehmens">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/19876.png" alt="Mit Licht geschossen | 53. Bildpräsentation">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/20084.png" alt="Splu Experts GmbH: Daniel Düsentrieb meets DIN">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/20244.png" alt="SIESTA-Lesung">"
    "<img src="https://www.tu-chemnitz.de/tu/termine/image/20099.png" alt="Willkommen an Sachsens Schulen! Praktikum – Vorbereitungsdienst – Schuldienst">"

For each string, I need the only information starts after "alt" and text before alt should be discarded

For example, with string 1, I only need information "Optimizing application documents">"

Could you help me by providing guidance on how can I do it?

I have learned about function "regexprep", but I do not know, how to implement it here.

Answer 1

[Rik]

Try something like this:

expr='(.*alt=")';
regexprep(str,expr,'')

Answer 2

[dpb]

Alternatively, there's the new(ish) extractAfter function that was introduced with the new strings class...

>> extractAfter(s,"alt=")
ans = 
    ""Optimizing application documents">"
>> 

Answer 3

[Raj Tailor]

Thank you so much Rik and dpb,

The solution worked for me, much appreciated.