flip a matrix using loops

hi,

im tring to flip a matrix usind withot the flip function

for ex:

[1 3 -2; -4 4 8; 7 -1 3] will cange to [7 -1 3; -4 4 8; 1 3 -2]

my script is

outFlip(i,:)= inMatrix(size(inMatrix,1)+1-i,:); 

Answer 1

[Jan]

Your line is correct already. Only the loop is missing:

n = size(matrix, 1);
for k = 1:n
  outFlip(k,:) = inMatrix(n - k + 1, :);
end

Without the loop:

n = size(matrix, 1);
outFlip = inMatrix(n:-1:1, :);

[Stephen23]

+1 simple without the loop.

Answer 2

[madhan ravi]

matrix=randi([0,4],2);
outFlip=zeros(size(matrix,1),size(matrix,2));
for  i= 1:size(matrix,1) 
    for j=1:size(matrix,2)
       outFlip(j,i)=matrix(i,j);  % just swap the indices
    end
end

[Ariela Glikman]

no, i mean:

[1 3 -2; -4 4 8; 7 -1 3] will cange to [7 -1 3; -4 4 8; 1 3 -2]

[madhan ravi]

ok then:

matrix=[1 3 -2; -4 4 8; 7 -1 3];
ctr=1;
outFlip=zeros(size(matrix,1),size(matrix,2));
for  i=size(matrix,1):-1:1
       outFlip(i,:)=matrix(ctr,:);  % just swap the indices
    ctr=ctr+1;
end
outFlip