Add date variable into Xlsread Syntax?? Needs Help!!

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Xiao Tang
Xiao Tang el 16 de Jul. de 2012
Guys I really need some help here!
There are mutiple similar xlsx files mamed after date, '199001.xlsx'(Jan 1990),'199002.xlsx','199003.xlsx'... Those files include data in different dates with accuracy in month.
The first step is to use MATLAB to do manipulate the data in one month/file. Then do a loop(since the manipulation algorithm for each month is the same), and pull out all the results in the same spreadsheet.
I've done the manipulation for one month. My problem right now is:
How can to make the date a variable when using xlsread?
Case 1, when I use
[~, ~, XXX] = xlsread('C:\Users...\199001.xlsx','Sheet1','E3:E502')
How can I make the part '199001' a variable?
Except for adding a variable to xlsread syntax, it is more challenging when '199001' is a date because the series should be:
199001,199002,199003... 199011,199012,199101(not '199013'!),199102...
So it's not a simple i = i+1 loop.
%%%%%%%%%%%%%
Case 2
There is another file called Economics.xls containing Economics information for all months. Part of the whole spreadsheet is like
When the loop comes to '199708' I should read data in Row 2, i.e., 5.54,0.00,2.23.
The code is
XXX = xlsread('C:\...\Economics.xls','Sheet1','B2:D2')
How can I make Row 2 as a variable according to the first column(the date)? It looks like this should be the same variable in Case 1.
Your opinion is very important!

Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 16 de Jul. de 2012
Editada: Andrei Bobrov el 16 de Jul. de 2012
case 1
in case: your files from 199001.xlsx to 199108.xlsx
b = diff(datevec({'199001';'199108'},'yyyymm'));
mns = b(1:2)*[12;1];
a = cellstr(datestr(datenum(1990,1+(0:mns)',1),'yyyymm'));
XXX = cell(size(a));
[~,~,XXX] = cellfun(@(x)xlsread(fullfile(yourpath,[x,'.xlsx']),'Sheet1','E3:E502'),a,'un',0);
  3 comentarios
Andrei Bobrov
Andrei Bobrov el 17 de Jul. de 2012
please try this is code:
[Y M] = datevec(datenum({'199001';'199108'},'yyyymm'))
mns = diff([Y M])*[12;1]
a = cellstr(datestr(datenum(1990,1+(0:mns)',1),'yyyymm'))
Xiao Tang
Xiao Tang el 17 de Jul. de 2012
It's perfect! Thanks

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