Finding absolute difference between each row of a tall array

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Osman
Osman el 22 de Dic. de 2018
Comentada: Osman el 24 de Dic. de 2018
I am trying to find sum of absolute differences of each row. So if the input matrix A is M x N, the output matrix B should be M x M and
B( i , j ) = sum(abs( A ( i , : ) - A ( j , : ))). For small matrices the below two codes work.
lng=size(A,1);
B=reshape(sum(abs(repelem(A,lng,1)-repmat(A,lng,1)),2),lng,lng);
OR
lng=size(A,1); wdt=size(A,2);
B=zeros(lng);
for i=1:wdt
B=B+abs((A(:,i)-A(:,i)'));
end
The problem is that A is a tall matrix with dimension M larger than N. Thus, I cannot apply neither of these two methods on it. For the first code, it doesn't allow me to give the first inputs of repelem and repmat commands something different than 1. For the second code, taking the transpose fails for the tall array (is that forbidden totally for tall arrays or is there a workaround?) . Can someone please help me on this? I would appreciate if it would be a vectorized code.
Thanks in advance.
  1 comentario
madhan ravi
madhan ravi el 24 de Dic. de 2018
Editada: madhan ravi el 24 de Dic. de 2018
probably Edric Ellis can share some light , he is really an expert on this (tall arrays)..

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Respuestas (1)

Cris LaPierre
Cris LaPierre el 24 de Dic. de 2018
I would use the diff function.
First, check that the function(s) you want to use are compatible with tall arrays. See this page.
I would probably use abs(diff()).
There is a note on the limitations for diff with tall arrays:
  • You must use the three-input syntax Y = diff(X,N,dim).
  1 comentario
Osman
Osman el 24 de Dic. de 2018
Unfortunately, diff does not work for me in this case. It only takes the difference between consecutive rows but I need the differences of a single row to all other rows of the matrix. Basically, I am trying to implement what pdist function does but it is not compatible with tall arrays. At the end, the code will be used for a knn Imputation method so if there is an easier way to apply it to tall arrays that will be really helpful. Still thanks for the advice :)

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