plot of inverse laplace of a function

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azam ghamari
azam ghamari el 26 de Dic. de 2018
Comentada: Jerom John Shibu el 3 de Mayo de 2021
Hi Guys
I am writing this code: but it doesn't plot, it gives me error.
Error using plot
Data must be numeric, datetime, duration or an array convertible to
double.
Error in test2 (line 43)
plot(t,h(t))
May every body know and inform me? Thanks
syms t
U=laplace(0.1*exp(2.44*t));
syms s
G=(s-2.44)/((s+5)*(s+6)*(s+7));
H=G*U;
t=1:0.01:100;
h(t)=ilaplace(H);
plot(t,h(t))
  2 comentarios
Jerom John Shibu
Jerom John Shibu el 3 de Mayo de 2021
try explot( x(t), [ 0 30])
Jerom John Shibu
Jerom John Shibu el 3 de Mayo de 2021
ezplot

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Respuesta aceptada

madhan ravi
madhan ravi el 26 de Dic. de 2018
syms t s
U=laplace(0.1*exp(2.44*t));
G=(s-2.44)/((s+5)*(s+6)*(s+7));
H=G*U;
h=matlabFunction(ilaplace(H));
t=1:0.01:100;
plot(t,h(t))
Screen Shot 2018-12-26 at 10.10.21 AM.png

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