about why in pole placement gives me error?
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azam ghamari
el 26 de Dic. de 2018
Comentada: oussama sadki
el 5 de Sept. de 2022
Hi guys
Does every body knows why in the system :
s=tf('s');
G=(s-2.44)/((s+5)*(s+6)*(s+7));
[A,B,C,D]=tf2ss([1 2.44],[1 18 107 210]);
k_max=1001;
for j=1:k_max
p(j,:)=[-j-1 -3*j -j-2];
K(j,:)=place(A,B,p(j,:));
end
with differeing the p value it gives me this error?
Error using place (line 78)
The "place" command cannot place poles with multiplicity greater than rank(B).
Error in test2 (line 33)
K(j,:)=place(A,B,p(j,:));
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Aquatris
el 27 de Dic. de 2018
It is just the error says. Place command cannot place poles with multiplicity greater than rank(B). In your case, rank(B) is 1. However when j=1, you want to place your poles at [-2 -3 -3]. You see the multiplicity of pole at -3 is 2. So place command cannot be used. If you start j from 2 instead of 1, there won't be an issue.
7 comentarios
Aquatris
el 28 de Dic. de 2018
I dont know why you think it does not work. You do realize place is for state feedback not output feedback so you need an observer right?
oussama sadki
el 5 de Sept. de 2022
hello Aquatris, why then rank(B) and each one poles multiplicity should be equal so that feedback gain could be computed, what relationship is there?
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azam ghamari
el 28 de Dic. de 2018
2 comentarios
Aquatris
el 28 de Dic. de 2018
This error is not because of place function. Just check the size of the matrix place() function return with given A and B matrice and you will realize the error.
Since this is a 2 input 4 state system, place() will return a 2x4 matrix. With the line "K(j,:) = place(...)" you are trying to assign 2x4 matrix to a 1x4 matrix, hence the error dimension mismatch. A quick fix is to change the line to;
K(j,:,:)=place(A,B,p(j,:))
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