Counting the unique values
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I have a values
out=
c1 c2,,,,,,,,,,,,,,,,,,,,,c5
'gene1' 'd' 'u' 'd' 'u' 'd'
'gene2' 'u' 'u' 'u' 'u' 'd'
'gene3' 'u' 'u' 'd' 'u' 'u'
'gene4' 'd' 'u' 'u' 'd' 'd'
'gene5' 'u' 'u' 'u' 'u' 'd'
'gene6' 'd' 'u' 'u' 'u' 'u'
'gene7' 'd' 'u' 'd' 'u' 'u'
Taking the first column 'c1' value for gene1 is 'd' this value must be compared with all other column if there is more than 3 same vales it should be displayed,,Only first clumn must be compared with others columns
in 1st col there are 3d's ,2nd col 4u's(since 1st col is u),3rd col
4u's,,,,,,,,,,,6&7th gene's there are only 1 ans 2 d's respectively,so it should be deleted
So i need output as
'gene1' 'd' 'u' 'd' 'u' 'd'
'gene2' 'u' 'u' 'u' 'u' 'd'
'gene3' 'u' 'u' 'd' 'u' 'u'
'gene4' 'd' 'u' 'u' 'd' 'd'
'gene5' 'u' 'u' 'u' 'u' 'd'
Pleae help
1 comentario
Respuesta aceptada
Freddy
el 18 de Jul. de 2012
Hello Pat,
first idea i came up with:
A = {'','c1','c2','c3','c4','c5';
'gene1' 'd' 'u' 'd' 'u' 'd';...
'gene2' 'u' 'u' 'u' 'u' 'd';...
'gene3' 'u' 'u' 'd' 'u' 'u';...
'gene4' 'd' 'u' 'u' 'd' 'd';...
'gene5' 'u' 'u' 'u' 'u' 'd';...
'gene6' 'd' 'u' 'u' 'u' 'u';...
'gene7' 'd' 'u' 'd' 'u' 'u'};
limit = 3;
F = cell2mat(A(2:end,2:end));
A(logical([0;sum(bsxfun(@eq,F,F(:,1)),2)>=limit]),:);
Hopefully it will help you.
Freddy
1 comentario
Jan
el 18 de Jul. de 2012
You can omit the "logical", if you use:
A([true; sum(bsxfun(@eq, F, F(:,1)), 2) >= limit], :)
Más respuestas (2)
Walter Roberson
el 18 de Jul. de 2012
c1_column = 2; %looks like column 2 to me, since column 1 has gene name
match_count = arrayfun(@(K) sum(out{K,cl_column} == [out{K,c1_column+1:end}]), 1:size(out,1));
out(match_count > 3, :)
Your problem description is inconsistent about what to do if the number of matches is exactly 3. You wrote that it has to be more than 3, but your sample output includes the case where it is exactly 3.
2 comentarios
Jan
el 18 de Jul. de 2012
@Pat: Come on, I'm sure you are able to fix this typo by your own. The "1" (one) looks very similar to the "l" (lowercase L). It is your job to participate as far as possible in the solution of your problems.
Bjorn Gustavsson
el 18 de Jul. de 2012
Pat,
I strongly suggest you change the encoding of your data! Make your variable an integer array with for example 0 for 'd' and 1 for 'u'. Then you could do something like this:
genes = [0,1,0,1,0
1 1 1 1 0
1 1 0 1 1
0 1 1 0 0];
lim4disp = 3;
genes(sum(repmat(genes(:,1),[1,size(genes,2)]) == genes,2)>=lim4disp,:)
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