datetime function vertical line
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Lieke Numan
el 5 de Feb. de 2019
Comentada: Lieke Numan
el 6 de Feb. de 2019
I have a plot where I use a datetime vector for x-axis (see example below). Now I want to make a vertical line within this plot, but when i use this:
x=17-Aug-2017 09:37:00
line([x x],[0 50])
I get this error:
Error using matlab.graphics.axis.decorator.DatetimeRuler/makeNumeric
Cannot combine or compare a datetime array with a time zone with one without a time zone.
Error in matlab.graphics.internal.makeNumeric
Example of first three samples in my datetime vector of my originally plotted data:
15-Aug-2017 17:58:58
15-Aug-2017 18:00:58
15-Aug-2017 18:02:58
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Respuesta aceptada
Steven Lord
el 6 de Feb. de 2019
From the error message, you've plotted some datetime data that includes time zone information. If you do that, and you want to use line, xline, or yline you need to specify a datetime that includes time zone information in that *line call. Let's make two datetime objects, one with a time zone and one without.
withTZ = datetime('today', 'TimeZone', 'America/New_York')
withoutTZ = datetime('today')
Now let's make some data to plot.
v = 0:5;
x = withTZ + days(v);
plot(x, v.^2);
If we were to try to make an xline using withoutTZ, it would fail. But if we make one using withTZ, it works.
xline(withTZ + days(2.5)); % Works
xline(withoutTZ + days(1.5)); % Fails
Más respuestas (2)
Adam Danz
el 5 de Feb. de 2019
You're probably not using datetime formated variables. This works:
dt = datetime({'15-Aug-2017 17:58:58'
'15-Aug-2017 18:00:58'
'15-Aug-2017 18:02:58'});
figure
plot(dt, [40 45 50], '-o')
x=datetime('17-Aug-2017 09:37:00') % <-- make sure it's actually 'datetime'
line([x,x],[0 50])
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