for loop produces a 103x1 array I need a 1x103 array.

How do I get this for loop to produce a 103X1 array? I do not want to use the transpose function.

for ii = 1:numel(H)
    if H(ii) <= 11
        P_S(ii) = (101.325)*((288.15/(STemp_K(ii)))^-5.255877);
    elseif H(ii) >= 11 && H(ii) <= 20
        P_S(ii) = (22.632)^(-0.1577*(H(ii)-11));
    elseif H(ii) >= 20 && H(ii) <=32
        P_S(ii) = (5.4749)*((216.65/(STemp_K(ii)))^34.16319);
    elseif H(ii) >= 32 && H(ii) <=47
        P_S(ii) = (0.868)*((228.65/(STemp_K(ii)))^12.2011);
    elseif H(ii) >= 47 && H(ii) <=51
        P_S(ii) = (0.1109)^(-0.1262*(H(ii)-47));
    end
end

Answer 1

[dpb]

Write

P_S(ii,1)...

But, why use a loop at all--use the vector functions in Matlab instead. I've not tried to decipher the RHS to see what simplifications might be made in writing a more general functional form, but at worst you simply write

ix=H<11;
P_S(ix) = 101.325*288.15./STemp_K(ix)^-5.255877;
ix=iswithin(H,11,20);
P_S(ix) = 22.632.^-0.1577*(H(ix)-11);
...

where iswithin is my "syntactic sugar" utility routine

>> type iswithin

function flg=iswithin(x,lo,hi)
% returns T for values within range of input
% SYNTAX:
%  [log] = iswithin(x,lo,hi)
%      returns T for x between lo and hi values, inclusive

  flg= (x>=lo) & (x<=hi);
>> 

NB: the "dot" operators to do element-wise operations on the vector sections...

You might note that your conditions are not written exclusve in that you have the "=" on both bounds so the lower limit of the second conditional overlaps the upper limit of the first, and so on...this may not be an issue, just noting...

[Adam Kevin Francis Baker]

Thank you for answering my original question. Your notes were also appreciated. The reason the conditions are set up like that is because I got them from a table which had them written out...see attached. Also, I'm going to continue using the for loop because I'm still learning and thats what I was taught in class.