Vector as Function Input

I want to find a way to pass the inputs to a function as a vector instead of having to specify the individual inputs to the function. I want to do this because I have another function that takes in a function handle as its input as well the input values to that function to generate a set of sigma points(I'm writing a ukf). It looks a bit like this(very over-simplified

function [x]=myFunc(func_handle,func_input)
    x = func_handle(func_input)
end

Now the issue is in my implementation of the func_handle, if I declare a function as follows, I have no issues.

test_func = @(x)[x(1) + x(2); x(2)^2; x(1)^2 + x(3)^2];

But for my application, my function is very long and complex and can't be written in a single line as such so I have it written in terms of symbolic expressions. But when written as such, I can't get it to work right. I could use some help with being able to define the function such that the input values can be given as a vector so it can be used in the above function properly.

%% Function Test
clear all
close all

syms a b c
test1 = b+a;
test2 = b^2;
test3 = a^2 + c^2;
test = [test1;test2;test3];
test_func = @(input)[test1;test2;test3];

test_input = [1;2;3];
test_func(test_input)     %This doesn't work

test_func = matlabFunction(test);
test_func(test_input(1),test_input(2),test_input(3))     %This works but input can only be one size

Answer 1

[madhan ravi]

% Function Test
syms a b c
test1 = b+a;
test2 = b^2;
test3 = a^2 + c^2;
test = [test1;test2;test3];
test_input = num2cell([1;2;3]);
test_func = matlabFunction(test);
test_func(test_input{:})  % have a look here

[Cory Ibanez]

So the input to the function is going to be what is returned from the function. I defined the test_input just as an example but in reality it is a returned vector of variables. Can you convert a vector test_input = [1;2;3]; to a cell array? Without changing the actual defining of the variable in the first place.

[madhan ravi]

num2cell() converts it into a cell array ,

"Without changing the actual defining of the variable in the first place."

I have no idea whatever that you mean by that.

[Cory Ibanez]

I wasn't sure if num2cell would only apply in the actual defining of the input values. I tested it out and I now see I can do:

test_input = [1;2;3];
test_input = num2cell(test_input);

This should solve my issue thanks!