How to replace variable name in function handle?
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Kalore Shubham Arun
el 25 de Feb. de 2019
Comentada: Marco Aurélio
el 9 de Jul. de 2024
I have a function handle as given below
f = @(x1,x2) x1*x2
and I want to change variable name to
f = @(x) x(1)*x(2)
Please help me
Thanks
PS: The function is just for illustration purpose
1 comentario
Marco Aurélio
el 9 de Jul. de 2024
Hello Matlab mate.
I think you must redefine de function handle just rewriting like this:
f=@(x) prod(x);
Respuesta aceptada
Stephan
el 25 de Feb. de 2019
Editada: Stephan
el 25 de Feb. de 2019
Hi,
for me this worked:
f = @(x1,x2) x1*x2
f = string(char(f));
f = replace(f,"@(x1,x2)","@(x)");
f = replace(f,["x1","x2"],["x(1)","x(2)"]);
f = str2func(f)
result is:
f =
function_handle with value:
@(x1,x2)x1*x2
f =
function_handle with value:
@(x)x(1)*x(2)
Best regards
Stephan
2 comentarios
madhan ravi
el 25 de Feb. de 2019
Editada: madhan ravi
el 25 de Feb. de 2019
stephen what if there are 100 inputs to the function handle? it would be not a good idea
Stephan
el 25 de Feb. de 2019
Editada: Stephan
el 25 de Feb. de 2019
You are right. But i think this function is worth to be shown here as an alternative for small examples. Maybe it is not the best / most efficient solution here. Yours is pretty nice - but the OP asked for how to replace variable names in a function handle - this is what i was answering to.
Más respuestas (1)
madhan ravi
el 25 de Feb. de 2019
Instead of converting it to your later need convert the vector as comma separated list using num2cell():
x=rand(1,2); % example vector
X=num2cell(x);
f(X{:}) % pass the vector all at once
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