Removing a syms variable from a For loop solution

Hello there, I am trying to create a for loop function for a simple formula that includes differentiation but I am getting the solution :

ans =

[ x, -2510341221049253/4503599627370496, 296951380318845/4503599627370496, -3448745601629/36028797018963968, 21572111/73786976294838206464, 0, 0]

which is correct but is there a way to remove the x? Here is my code. Any help is greatly appreciated!

function x = newton3(Func, x1, N)
syms x
F(x) = diff(Func(x));
%apply Newton's Method
a=Func(x1);
b=double(F(x1));

d = x1 - (a/b);

%apply Newton's Method
%ans=[;];
for i=1:N
    syms x;
    F(x) = diff(Func(x));
    a=Func(x1);
    b=double(F(x1));
    c=a/b;
    d(i) = x1 - c;
    x=[x,d];
    x1=d(i);
    
    %ans=[ans;x1];
%iterate through Newton's method N times and store results in vector
end

Answer 1

[Agnish Dutta]

Based on on the provided equation and code, here's something I came up with to calculate the neede values:

syms x
N = 100    % No. of itereations.

% I've taken a sample function to demonstrate. Simply replace the RHS of f(x) with your desired function.
f(x) = 5*x^2 - 3*x + 7;
f_prime(x) = diff(f(x));
x_init = f(0) / f_prime(0);

% An array to hold intermediate and the final values.
vals = [];
vals(1) = x_init;

% Loop to calculate the values in each iteration.
for i = 2:N
vals(i) = vals(i - 1) + f(i) / f_prime(i);
end

If however, you wish to keep the rest of your code intact and just remove the first element from the array that stores your result:

ans = ans(2: end)