Index exceeds the number of array elements in while loop

2 visualizaciones (últimos 30 días)
Kaan Uçar
Kaan Uçar el 25 de Mzo. de 2019
Comentada: Kaan Uçar el 13 de Abr. de 2019
I ve been trying to create a Fibonacci Sequence in which ratio of the adjacent values converge to 0.001. Here is the code I've written so far:
clc
clear
x = input('Please enter the first number in the series:');
y = input('Please enter the second number in the series:');
s(1) = x;
s(2) = y;
k = 3;
while abs(s(k)./s(k-1) - s(k-1)./s(k-2))>0.001
s(k) = s(k-1) + s(k-2)
k = k+1;
end
disp(s)
But when I run the code, it says; Index exceeds the number of array elements (2)
Error is on the eighth line.
  3 comentarios
Kaan Uçar
Kaan Uçar el 25 de Mzo. de 2019
I defined s(3) as x + y and and still get the error. This time in parantheses it says 3 instead of 2.
Kevin Phung
Kevin Phung el 25 de Mzo. de 2019
Editada: Kevin Phung el 25 de Mzo. de 2019
ok, and where is that in your code? What is see is that you've set s(1) and s(2) to be the user input.
Youve made k a constant 3, and your while loop CONDITION:
while abs(s(k)./s(k-1) - s(k-1)./s(k-2))>0.001
starts with s(k) which is s(3), and that does not exist.

Iniciar sesión para comentar.

Respuesta aceptada

Raghunandan V
Raghunandan V el 26 de Mzo. de 2019
Hi,
I just shuffled the code a bit. Check this:
clc
clear
x = input('Please enter the first number in the series:');
y = input('Please enter the second number in the series:');
s(1) = x;
s(2) = y;
k = 3;
Cond =1; % intialize the condition
while Cond > 0.001
s(k) = s(k-1) + s(k-2);
Cond = abs(s(k)/s(k-1) - s(k-1)/s(k-2));
k = k+1;
end
disp(s)
  1 comentario
Kaan Uçar
Kaan Uçar el 13 de Abr. de 2019
Sorry for the late response. I got the problem fixed. Thank you for your helps.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by