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need help with fprintf

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Jung
Jung el 26 de Mzo. de 2019
Comentada: Walter Roberson el 27 de Mzo. de 2019
Hi all,
I have this line of script where it takes a parameter text file (par.txt) and changes the variables for calibration purpose.
fout=fopen('par.txt','w+')
fprintf(fout,'wcwp\t%6f\t%6f\t%6f\t%6f\t%6f\r\n', x(1),x(1),x(1),x(1),x(2));
Here, I'd like to implement this line so I can increase the values at a same rate as the other varialbes
fprintf(fout,'wcwp\t0.4*%6f\t0.4*%6f\t0.4*%6f\t0.4*%6f\t0.4*%6f\r\n', 0.4,0.4,0.4,0.4,0.8);
But, once I run this script, my output looks like this;
wcwp 0.4*0.400000 0.4*0.400000 0.4*0.400000 0.4*0.400000 0.4*0.800000
I need to find a way where I can have %6f value multiply by something and still show the final answer to the txt file
Any help would be appreciated

Respuestas (1)

Walter Roberson
Walter Roberson el 26 de Mzo. de 2019
fprintf(fout,'wcwp\t%6f\t%6f\t%6f\t%6f\t%6f\r\n', 0.4*([x(1),x(1),x(1),x(1),x(2)]);
  2 comentarios
Jung
Jung el 27 de Mzo. de 2019
Thanks for the reply.
What if instead of fixed value, such as 0.4 in the example, I'd like a range of value for x(1)... so that whenever I calibrate the data, the rate/percentage of differences is constant for x(1) and x(2).
For instance, I would want my parameters to be calibrated within the 10% range so [0.9 to 1.2] so these values would be multiplied by variables
Walter Roberson
Walter Roberson el 27 de Mzo. de 2019
Change the 0.4 to a variable name of a variable you calculate just before this.

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