How to use a for-loop to find the onset (first element) of trials of zeros, ones and twos, in an array of sequences of zeros, ones and twos
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
I am trying to make a function that finds the onsets (three different) trials (in this case, the trial starts when a new sequence of zeros, ones and twos starts in an array of numbers, this array of numbers always consists of sequences of ones, zeros and twos).
See the example of such an array (E) for a clarification:
E = [zeros(1,10) ones(1,5) zeros(1,8) 2*ones(1,4) zeros(1,12)]
This array is always a rowvector. The example consists of 5 trials, and 39 elements (10+5+8+4+12).
With the funtion, I want to find the elements (1:39) of the starts of every trial: [start_of_trial], with the corresponding value 0, 1 or 2: [trial_value]. This way, the function will be as follows:
[start_of_trial, trial_value] = find_onsets(E)
How can I use a for-loop to make this function work? I tried several things, but nothing worked properly
0 comentarios
Respuestas (2)
Andrei Bobrov
el 31 de Mzo. de 2019
function [start_of_trial, trial_value] = find_onsets(E)
start_of_trial = find([1;diff(E(:))~= 0]);
trial_value = E(start_of_trial);
end
Catalytic
el 31 de Mzo. de 2019
No, we're not going to do your homework for you. Go away and leave us alone.
0 comentarios
Ver también
Categorías
Más información sobre Startup and Shutdown en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!