Pre-locating an array
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    Susan
 el 10 de Abr. de 2019
  
    
    
    
    
    Comentada: Susan
 el 10 de Abr. de 2019
            Hi MATLAB guys, 
I got stuck at some point and really appreciate your help.
Do you know how can I pre-locate the value of X in the following code? X is a matrix and for each i and j its dimentions will change. For example for given i and j, X has a dimention of Ri * Tj. 
N = [1 2 3 4 5 6 7 8 9 10];
M = [11 22 33];
X === zeros  %%%%pre-locating here
for k = 1 : 10
    for m = 1 : N(k)
       for i = 1 : 3;
         for j = 1: M(i)
              X(:,:, j,i,m,k) = sth;
        end
      end
   end
end
Thanks in advance
2 comentarios
Respuesta aceptada
  James Tursa
      
      
 el 10 de Abr. de 2019
        
      Editada: James Tursa
      
      
 el 10 de Abr. de 2019
  
      Numeric arrays must be rectangular. You cannot have different dimensions for different slices.  To get that behavior you would need to use something like a cell array to store your different sized variables. E.g.,
X{j,i,m,k} = sth;
But, even though the contents of the cell array elements do not all have to be the same size, the cell array itself must be rectangular. You could still use it in your above scheme as long as it was OK to have a bunch of empty cells in the spots you were not using.
3 comentarios
  Rik
      
      
 el 10 de Abr. de 2019
				
      Editada: Rik
      
      
 el 10 de Abr. de 2019
  
			You can use the code James suggested, and you can do it like this:
N = [1 2 3 4 5 6 7 8 9 10];
M = [11 22 33];
X=cell(max(M(:)),numel(M),max(N(:)),numel(N));
for k = 1 : numel(N)
    for m = 1 : N(k)
       for i = 1 : numel(M)
         for j = 1: M(i)
             X{j,i,m,k} = sth;
         end
       end
    end
end
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