Row index exceeds matrix dimensions

Hi
I have a 143x4 matrix, which looks like this
A=[ 1 556037.025 6237642.046 5.964;
1 556037.035 6237642.041 5.960;
1 556037.028 623742.041 5.967;
2 556032.654 623730.067 10.368;
2 556032.652 623730.060 10. 364;
4 556042.000 623730.000 5.000;
4 556042.002 623730.005 5.010] ;
Column 1 is the point number, column 2-4 are X,Y,Z coordinates.
Each point is measured between 1 and 5 times.
My code is:
A=load('Test.txt');
A=sortrows(A);
T=array2table(A);
m=varfun(@mean,T,'GroupingVariables',1);
out=A;
out(:,2:end)=out(:,2:end) - m{A(:,1),3:end}
I get the error Row index exceeds table dimensions
I have tried to test different scenarios and the error occurs when a point is missing, for example if there is no point number 7, so the first column goes from 6 to 8.
Any idea what is wrong?

4 comentarios

KSSV
KSSV el 24 de Abr. de 2019
Which line is givng you the error? I think what you have shown is not a complete code.
Peter Larsen
Peter Larsen el 24 de Abr. de 2019
The error is caused by this line:
out(:,2:end)=out(:,2:end) - m{A(:,1),3:end}
Peter Larsen
Peter Larsen el 24 de Abr. de 2019
The complete code is updated now
Peter Larsen
Peter Larsen el 24 de Abr. de 2019
Hi
It works until the numbers in column 1 skips a number (See updated revision). If the point number skips from 2 to 4 without having a point number 3, the error occurs

Iniciar sesión para comentar.

 Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 24 de Abr. de 2019

1 voto

T = array2table(A);
m = varfun(@mean,T,'GroupingVariables',1);
out = A;
[~,~,ii] = unique(A(:,1));
out(:,2:end) = out(:,2:end) - m{ii,3:end};

Más respuestas (0)

Categorías

Productos

Versión

R2018b

Preguntada:

el 24 de Abr. de 2019

Comentada:

el 24 de Abr. de 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by