Replace Nan by a number in a cell array
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Susan
el 26 de Abr. de 2019
Comentada: Susan
el 30 de Abr. de 2019
Hey MATLAB guys,
I would like to replace all Nan in the following cell array r by a number. Could anyone please tell me how I can do that for the following problem? Thanks in advance
r = cell(sum(nL), numel(nL), numel(nW), max(nW(:)));
for k = 1 : numel(nW)
for m = 1 : nW(k)
for j = 1 : numel(nL)
for i = 1 : nL(j)
r{i + Nup*(j - 1), j, k, m} = .....
end
end
end
end
2 comentarios
Rik
el 26 de Abr. de 2019
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
Respuesta aceptada
Guillaume
el 26 de Abr. de 2019
Your question is not very unclear. You show a loop filling (part) of a cell array with ... something unspecified. Presumably, that something is a matrix or vector of varying size and not a scalar (otherwise you wouldn't be using a cell array) and maybe part (all?) of it can be NaN.
If you don't want NaNs in the something, simply replace them before copying the something in the cell array:
for ...
for ...
something = ...
something(isnan(something)) = somevalue; %replace NaNs by somevalue
r{..} = something;
end
end
Más respuestas (2)
Rik
el 26 de Abr. de 2019
You can use the isnan function:
r = cell(sum(nL), numel(nL), numel(nW), max(nW(:)));
for k = 1 : numel(nW)
for m = 1 : nW(k)
for j = 1 : numel(nL)
for i = 1 : nL(j)
if isnan(r{i + Nup*(j - 1), j, k, m})
r{i + Nup*(j - 1), j, k, m} = .....
end
end
end
end
end
4 comentarios
Rik
el 27 de Abr. de 2019
That seems like it should work, yes. I just wrote the code like that because you didn't mention any context of your question, so it was/is a bit difficult to give sensible advice. You can also have a look at Guillaume's suggestion, maybe that suggestion works better for your situation.
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