eliminate indices that are empty

Suppose I have a vector of eliments including empty spaces in random places. How can I get the average of values that are available.

Example is as follows. Note that there is no value after 1 and 8. So I want to avoid those and get the average of the rest. Here I cannot just use the 'mean(x,1)' because empty indexes. Assume that I am considering a large vector and i cannot find the indices where there are no values, but just empty spaces.

X=[ 2 4 1 5 2 2 7 8 1 3]

Answer 1

[madhan ravi]

X={ 2  4  1  []   5  2  2  7  8   []   1  3};
idx=cellfun('isempty',X);
X(idx)={NaN};
Wanted=mean([X{:}],'omitnan')

%or
Wanted=mean([X{~idx}])

[Thishan Dharshana Karandana Gamalathge]

Thanks. But I was looking for a one line answer. Earlier I remember using the backslash ("\" ) symbol to get rid of unwanted. Whether a one line coding to get the average of values in the vector is possible, if i know the indices of missing data?

[madhan ravi]

Thishan Dharshana Karandana Gamalathge:

This is the one line method

Wanted=mean([X{:}],'omitnan')

[madhan ravi]

That's exactly what was posted.