cell2mat conversion

please help me to convert 1*28 cell in which each cell contains 10*25 size matrices.
i tried this
cell2mat(matrix)
it gives 10*7000 matrix
help me to convert it to double matrix
help me to solve this
Thanks in advance

3 comentarios

Stephen23
Stephen23 el 22 de Mayo de 2019
Editada: Stephen23 el 22 de Mayo de 2019
Twenty-eight cells each containing a 10x25 numeric array gives
>> 28*10*25
ans = 7000
seven thousand numeric elements. You request a numeric array with only twenty-eight numeric elements. What do you want to do with the other six-thousand, nine-hundred and seventy-two numeric elements?
Leela Sai Krishna
Leela Sai Krishna el 22 de Mayo de 2019
I am not clear in previous question.
I just edited my question.
Thanks
Catalytic
Catalytic el 22 de Mayo de 2019
Editada: Catalytic el 22 de Mayo de 2019
It is even less clear now. You removed any description of what you expect the result to be. Initially you said you wanted a 1x28 double vector as a result. As Stephen has already told you, the process you want for reducing your 10x25 matrix to a single number needs to be explained.

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Respuestas (10)

Matt J
Matt J el 22 de Mayo de 2019
Editada: Matt J el 22 de Mayo de 2019

1 voto

cellfun(@(c) c(1), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) mean(c(:)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) std(c(:)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) sum(c(:)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) max(c(:)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) min(c(:)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

cellfun(@(c) var(sum(c,2)), your_1x28_input)
Matt J
Matt J el 22 de Mayo de 2019

0 votos

ones(size( your_1x28_input))
Jos (10584)
Jos (10584) el 22 de Mayo de 2019

0 votos

Do you want to convert the 1-by-28 cell array C, each cell holding a 10-by-25 double matrix to a 3D double array M of size 10-by-25-by-28?
M = cat(3, C{:})

4 comentarios

Leela Sai Krishna
Leela Sai Krishna el 22 de Mayo de 2019
yes it works.
But is it possible to store 28 cells(10*25) in matrix form
Jos (10584)
Jos (10584) el 22 de Mayo de 2019
I do not know what you mean by "store 28 cells (10*25) in matrix form"?
Can you give a smaller example (for instancem 2 cells (2*3) in matrix form)?
Leela Sai Krishna
Leela Sai Krishna el 22 de Mayo de 2019
i have 1*2 cell array
in which each cell contains 2*3 matrix
i.e
cell1 cell2
2*3 2*3
i am trying to store it in 2 matrices
Jos (10584)
Jos (10584) el 22 de Mayo de 2019
Your question is still unclear. Can you give a complete example of the output?
C = {[1 2 3 ; 4 5 6] ; [11 12 13 ; 14 15 16]} % 1-by-2 cell array
% OUT = ....

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Matt J
Matt J el 22 de Mayo de 2019

0 votos

But is it possible to store 28 cells(10*25) in matrix form
I'm starting to think you mean this
[Matrix1,Matrix2,..., Matrix28] = deal(yourCell{:})

1 comentario

Stephen23
Stephen23 el 23 de Mayo de 2019
Editada: Stephen23 el 23 de Mayo de 2019
You might be right...
@Leela Sai Krishna: if you are trying get the contents of the cell array as 28 separate variables, then be aware that in general splitting up data makes it harder to work with. Most likely the best solution would be to leave your data in that cell array just as it is, where it can be trivially accessed using indexing.
Also note that using numbered variables (e.g. M1, M2, ... M28) is a sign that code is badly designed, and generally such names lead beginners into writing slow, complex, buggy code that is hard to debug.

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