Problem using interp1 cubic
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I`m trying to inter a grapich but it`s wrong im using interp1 cubic
How should be

It looks wrong

Help.
Edit [21 Aug 2012, 12:45 BST - OK] Added Alex's answer here
x1=[ 1.0000 6.1000 10.1800 135.3000 136.5750....86.7650 83.2800]
y1=[ 1 23 40...... 2144 2152]
s=[1:0.1:95]
z=interp1(x1,y1,s,'cubic')
plot(s,z)
6 comentarios
Azzi Abdelmalek
el 21 de Ag. de 2012
post your data
Jan
el 21 de Ag. de 2012
How could we find out, what is wrong with the command you have used to create the wrong diagram without seeing the code? A suggestion for improvements must be based on wild guessing.
Oleg Komarov
el 21 de Ag. de 2012
@Alex: please use comments, do NOT create additional answers unless it is an answer to your problem.
Alex
el 21 de Ag. de 2012
Oleg Komarov
el 21 de Ag. de 2012
I think the problem is that it's not a function, i.e. you have multiple Ys for an X.
As Jose pointed out you might transpose the x with the y, interpolate and then re-transpose back.
Alex
el 21 de Ag. de 2012
Respuestas (2)
José-Luis
el 21 de Ag. de 2012
Try inverting your x y data
interp1(x,y,...) to interp1(y,x,...)
Cheers!
2 comentarios
Jan
el 21 de Ag. de 2012
Alex wrote: (Copied from Answer to the comment section:)
Don`t work
Jan
el 21 de Ag. de 2012
Posting the problem and further explanations by picture only is not efficient. We cannot reproduce your diagrams when you do not provide the data. Perhaps only your drawing method fails?!
Titus Edelhofer
el 21 de Ag. de 2012
1 voto
Hi,
the plot shows that it's not a function y = f(x) and also not a function x = g(y). So you will need to move to a 2D parametrization. Take a look at the function spline that can handle the case of an arbitrary trajectory in the plane, e.g. take a look at example 4 (the cirlce).
Titus
3 comentarios
Titus Edelhofer
el 21 de Ag. de 2012
I took another look at the image. The transpose should work, so ignore my answer ...
Alex
el 21 de Ag. de 2012
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