How to plot sine graph by using for loop?
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Xing Xing
el 5 de Jun. de 2019
Comentada: AZEEM IMTIAZ
el 4 de Ag. de 2019
I tried to use a for loop to plot a sine graph. The values are generated but then when I try to graph them, I get either an error or no graph. Here's my code:
for i = 0:0.1:2*pi
m=sin(i);
n=i;
plot(n,m,'-r');
hold on
end
2 comentarios
Respuesta aceptada
Alex Mcaulley
el 5 de Jun. de 2019
You don't need a loop, just:
theta = 0:0.1:2*pi;
plot(theta,sin(theta))
6 comentarios
AZEEM IMTIAZ
el 4 de Ag. de 2019
you need to define t as a continuous variable in the first line then apply for loop on the frequency as discrete values. so that each frequency point will sweep over the time that you have defined in the first line. hope this helps!
t=0:0.04:5;
hold on
for f=[0.7 1 1.5 2]
y=cos(2*pi*f*t);
plot(t,y)
end
Más respuestas (1)
Mohammad Alhashash
el 5 de Jun. de 2019
maybe that is what you need.
t= 0:0.01:2*pi;
m =sin(t);
t_plot = NaN(1,length(t));
m_plot = NaN(1,length(m));
u = 1;
for i = 1:length(t)
cla
t_plot(i) = t(u);
m_plot(i) = m(u);
plot(t_plot,m_plot)
drawnow
u = u + 1;
end
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