How to get the value of Radio buttons from App Designer

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Leon
Leon el 24 de Jun. de 2019
Comentada: Csanád Temesvári el 23 de Mzo. de 2021
Here is my radio button:
app.ButtonGroup
  • app.A_button
  • app.B_button
What I want to do is this:
Button A should be the default button. If the button A is stay pushed or the user does not do anything to this group of buttons, my button value should be 10. If Button B is pushed, my overall button value should be 14.
How can I achieve that? Sorry for the basic question. I'm new to app designer.
  2 comentarios
Geoff Hayes
Geoff Hayes el 24 de Jun. de 2019
Leon - what do you mean by button value? Is this a value that you use in some sort of calculation?
Leon
Leon el 24 de Jun. de 2019
Yes, it is a value I use for some later calculation.
We can derive these values fomr an if loop, I guess.
If Button A is slected
Val = 10
else
Val = 14
end
My problem is that I do not know how to specify the if sentence.
Thanks

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Adam Danz
Adam Danz el 24 de Jun. de 2019
Editada: Adam Danz el 24 de Jun. de 2019
The 'Value' property of the radio buttons returns a logical that is true when selected and false otherwise. Here's an example to follow below.
if app.Button1.Value %where "Button1" is the name of the first radio button
Val = 10
elseif app.Button2.Value
Val = 14
else
Val = 0;
end
Another way to do that is to use the 'SelectedObject' property of the ButtonGroup along with a switch-case.
switch app.ButtonGroup.SelectedObject.Text
case 'Button1' %where "Button1" is the name of the first radio button
val = 10;
case 'Button2'
val = 14;
otherwise
val = 0;
end
  11 comentarios
Adam Danz
Adam Danz el 22 de Mzo. de 2021
> Unable to resolve the name app.Alakzat_2D_ButtonGroup.SelectedObject.Text.
Take a look at your function,
function [] = plot_2D(~)
switch app.Alakzat_2D_ButtonGroup.SelectedObject.Text
It has no inputs.
You have to pass the app variable to it and there should be a warning in AppDesigner on that line of code indicating that you're not passing the app variable, unless this function is outside of AppDesigner.
Csanád Temesvári
Csanád Temesvári el 23 de Mzo. de 2021
Thank you so much!
Obviously, I ran into further problems after I fixed that one, but that's just programming :)

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