How to sort the elements of a matrix in a random order
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I have three matrix
A=[4,5,8,1,6,3]', B =[1,2,3,7,9,6]' and C=[3,1,2,4,7,9]'
and I want to generate X=[A B C] such that each element in A,B,C is randomly placed. I amusing Matlab 2007b
2 comentarios
Azzi Abdelmalek
el 28 de Ag. de 2012
each element in A,B,C is randomly placed before or after concatenation?
Respuesta aceptada
Sean de Wolski
el 28 de Ag. de 2012
Editada: Sean de Wolski
el 28 de Ag. de 2012
So you want each column to be sorted randomly but to still be in the column it came from?
A=[4,5,8,1,6,3]';
B=[1,2,3,7,9,6]';
C=[3,1,2,4,7,9]';
ABC = [A B C]; %concatenate
[~,idx] = sort(rand(size(ABC))); %random indexes
ABCrand = ABC(bsxfun(@plus,idx,0:size(ABC,1):(numel(ABC)-1))) %keep columns aligned
If you don't care about elements staying in their columns, just use randperm. Of course you could always use a for-loop with randperm above, but I won't miss any opportunity to insert a bsxfun somewhere :)
2 comentarios
Sean de Wolski
el 28 de Ag. de 2012
If you are on 2007b then you probably need a junk value instead of a '~'
[junk,idx] = sort(rand(size(ABC))); %random indexes
Más respuestas (3)
Matlabbey
el 28 de Ag. de 2012
maybe you could try making a new random matrix and sorting by those values.
0 comentarios
Azzi Abdelmalek
el 28 de Ag. de 2012
Editada: Azzi Abdelmalek
el 28 de Ag. de 2012
A=[4,5,8,1,6,3]', B =[1,2,3,7,9,6]', C=[3,1,2,4,7,9]'
nA=length(A);
a1=perms(1:nA);nA1=size(a1,1);
res=[A(a1(round(nA1*rand(1,1)),:)); B(a1(round(nA1*rand(1,1)),:)); C(a1(round(nA1*rand(1,1)),:))]
2 comentarios
Andrei Bobrov
el 28 de Ag. de 2012
abc = [A,B,C]
[~,idx] = sort(rand(size(abc)))
out = abc(sub2ind(size(abc),idx,ones(size(abc,1),1)*(1:size(abc,2))));
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