calculating the percentage for unique values

I have values 

result = 

      {6x4 cell}
      {5x4 cell}
      {4x4 cell}
      {3x3 cell}

''  'c1'  'c2'  'c3'
'Par1'  'P'  'P'  'P'
'Par2'  'SPSO'  'PSO'  'MPSO'
'Par3'  'PSO'  'PSO'  'PSO'
'Par4'  'MPSO'  'MPSO'  'MPSO'
'Par5'  'SPSO'  'PSO'  'PSO'

In result{1,1} i have 

''  'c1'  'c2'  'c3'
'Par1'  'P'  'P'  'P'
'Par2'  'SPSO'  'PSO'  'MPSO'
'Par3'  'MPSO'  'PSO'  'PSO'
'Par4'  'MPSO'  'MPSO'  'MPSO'
'Par5'  'PSO'  'SPO'  'PSO'

in par2 all values in 3 columns are different so it must be omitted

in par3 there are 3 numbers of PSO so the percentage is 60(3/5*100)

in par4 there are 3 numbers of MPSO so the percentage  is 60(3/5*100)

in par5 there a are 3 numbers of PSO(PSO is same as SPO OR POS) so the percentage is 60(3/5*100)

SAME WAY MPSO is same as PSOMor combination of these four words

please tell how to process

Answer 1

[Azzi Abdelmalek]

 nr=size(result,1)
 for k=1:nr
     A=result{k};
     [n,m]=size(A)
     for i1=2:n
        test(i1-1)=1
        p=perms(char(A(i1,2)))
        for j1=3:m
            test(i1-1)=and(min(min(ismember(p,char(A(i1,j1))))),test(i1-1));
        end
     end
     perc{k}=[100*(m-1)/(n-1)*test]'
 end

[kash]

May i know what is nr ,getting error undefined variable

[Azzi Abdelmalek]

nr is the length of your array result

 result = 

      {6x4 cell}
      {5x4 cell}
      {4x4 cell}
      {3x3 cell}

in this case nr=4

[kash]

    In fn{1,1}

    ''  'c1'  'c2'  'c3'
    'Par1'  'P'  'P'  'P'
    'Par2'  'SPSO'  'PSO'  'MPSO'
    'Par3'  'MPSO'  'PSO'  'PSO'
    'Par4'  'MPSO'  'MPSO'  'MPSO'
    'Par5'  'PSO'  'PSO'  'PSO'

    PAr2,Par3  must be omitted because unique values in c1,c2,c3 are  less than 2

    ''  'c1'  'c2'  'c3'   ''
    'Par1'  'P'  'P'  'P'    ''
    'Par4'  'MPSO'  'MPSO'  'MPSO' 60 
    Par5'  'PSO'  'PSO'  'PSO'  60

    in fn{2,1}
    ''  'c1'  'c2'  'c3'
    'Par2'  'S'  'S'  'S'
    'Par3'  'MPSO'  'PSO'  'PSO'
    'Par4'  'MPSO'  'MPSO'  'MPSO'
    'Par5'  'SOP'  'PSO'  'SPO'

    'Par3',must be omitted(only 2 unique values)

    ''  'c1'  'c2'  'c3'   ''

    'Par2'  'S'  'S'  'S'    ''

    'Par4'  'MPSO'  'MPSO'  'MPSO' 60
    'Par5'  'SOP'  'PSO'  'SPO'  60

    but not getting results like this,please provide assistance

Answer 2

[Azzi Abdelmalek]

% updated code

 clear;clc
result={{''  'c1'  'c2'  'c3'
    'Par1'  'P'  'P'  'P'
    'Par2'  'SPSO'  'PSO'  'MPSO'
    'Par3'  'MPSO'  'PSO'  'PSO'
    'Par4'  'MPSO'  'MPSO'  'MPSO'
    'Par5'  'PSO'  'PSO'  'PSO'},
    {''          'c1'  'c2'  'c3'
      'Par2'  'S'  'S'  'S'
      'Par3'  'MPSO'  'PSO'  'PSO'
      'Par4'  'MPSO'  'MPSO'  'MPSO'
      'Par5'  'SOP'  'PSO'  'SPO'}};
 nr=size(result,1)
 for k=1:nr
     A=result{k};test=[];
     [n,m]=size(A)
     for i1=2:n
        test(i1-1)=1
        p=sort(char(A(i1,2)))
        for j1=3:m
            test(i1-1)=and(isequal(p,sort(char(A(i1,j1)))),test(i1-1))
        end
     end
     perc=num2cell([100*(m-1)/5*test]');
     A{1,m+1}='perc';
     A(2:end,m+1)=perc;
     test=[1 test];
     A(test==0,:)=[]
     result{k}=A
 end
 result{1},result{2}

[kash]

[]  'c1'  'c2'  'c3'  'perc'
'Par1'  'P'  'P'  'P'  60
'Par4'  'MPSO'  'MPSO'  'MPSO'  60
'Par5'  'PSO'  'PSO'  'PSO'  60

   result{2,1}

[]  'c1'  'c2'  'c3'  'perc'
'Par2'  'S'  'S'  'S'  75
'Par4'  'MPSO'  'MPSO'  'MPSO'  75
'Par5'  'SOP'  'PSO'  'SPO'  75

in both the percentage must be same 60%(3/5*100)but why it differs

[Azzi Abdelmalek]

how do you calcul this percentage? in 3/5*100 what is 3 and what is 5?

[Azzi Abdelmalek]

ok, here how was calculated the perc

     perc=num2cell([100*(m-1)/(n-1)*test]');

%do you mean it should be

     perc=num2cell([100*(m-1)/5*test]');

[kash]

Azzi 3 is the number of columns it differs for each parameter and 5 is constant

[Azzi Abdelmalek]

i changed the code, is still there a problem?

[kash]

thanks Azzi i got the answer