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integral(exp(double integral)) ?===>integral of riemann

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Marwen Tarhouni
Marwen Tarhouni el 20 de Jul. de 2019
Comentada: Marwen Tarhouni el 21 de Jul. de 2019
Hi,
i have an equation to 3 unknown (x,y theta)
i try this code
a =2.2;
b =0:10:100;
r = 50;
for i = 1:length(b)
bin=100;
resultat=0;
for k=1:bin
y=k*r/bin;
eq1= @(x,theta) exp(-b(i).*(sqrt(x.^2.*(cos(theta)).^2+(x.*sin(theta)-y).^2).*x)) ;
In2=integral2(eq1,0,r,0,2*pi);
resultat=resultat+ exp(-a* (1-In2))*2*y/(r^2);
end
end
==== >result does not work correctly
  2 comentarios
John D'Errico
John D'Errico el 20 de Jul. de 2019
Without even looking more carefully at the numbers, as soon as I see this start:
exp(-3.7154e+05*d(i).*(
I will predict your problem is in the form of exponential underflows. The result will be numerical garbage.
Marwen Tarhouni
Marwen Tarhouni el 20 de Jul. de 2019
Editada: Marwen Tarhouni el 20 de Jul. de 2019
Without this number ,i removed it. It's important to me to solve this equation ,i try this code as solution of my equation but i dont know if it's correctly.

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Sulaymon Eshkabilov
Sulaymon Eshkabilov el 20 de Jul. de 2019
Hi,
In your code, the variable d is assigned instead of b on line 2: d= 0:10:100; When this is fixed then everything works ok.
You can also start your simulation with the command: clearvars
Good luck

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