how to stop changing of a variable?
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Enez Furkan Cihan
el 23 de Jul. de 2019
Function ...
...
if s<200
logic=1;
else
logic=0;
end
end
end
here I'll explain what I tryna make, assume 's' is a variable result of that firstly starting from 0 and having cumulative summation step by step. Till it arrives at 200, logic equals to 1, so far so good, where it arrives at 200, I want the logic be constant 0 always after at 200, the problem is 's' is decreasing after it got hit by 200. So that it starts to be '1' again. That's the thing I don't want it to be. If it happened in a loop, I'd use 'break', but loops is not used.
For any help, I thank you for your time in advance.
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Stephen23
el 23 de Jul. de 2019
Editada: Stephen23
el 24 de Jul. de 2019
Use a nested function:
logic = true;
...
function ...
...
logic = logic && s<200;
...
end
...
Or a persistent variable:
5 comentarios
Stephen23
el 24 de Jul. de 2019
@Enez Furkan Cihan: I am glad that my suggestion of using peristent helped you. You can help me by voting for my answer or accepting it.
Más respuestas (1)
Image Analyst
el 23 de Jul. de 2019
Instead of this
if s<200
logic=1;
else
logic=0;
do this
logic = s < 200; % Just one line, not a whole if/else block.
if logic
return; % Exit out of the function entirely so s does not get altered anymore.
end
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