Which way is better?
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Note: This is not about preallocating variable in a loop. This is for general case.
For instance:
a(10,10) = 10; % the rest are filled with zeros
%or
a = zeros(10,10);
a(10,10) = 10;
4 comentarios
Walter Roberson
el 15 de Ag. de 2019
There was a Question in which people did some timing. The answer is not always obvious.
The larger question at the time also asked about the timing of assigning a constant to the matrix. For example is
5*ones(10,10)
faster than
5+zeros(10, 10l
Or
repmat(5, 10, 10)
madhan ravi
el 15 de Ag. de 2019
Walter Roberson
el 15 de Ag. de 2019
madhan ravi
el 15 de Ag. de 2019
Respuestas (1)
In terms of speed, the 2nd option is 3.0 times faster on average (p<0.0001, Wilcoxon Signed Rank; 1 million individually timed iterations of the following 2 options).
a = []; % to reset a upon each loop
a(10,10) = 10;
% versus
a = []; % to reset a upon each loop
a = zeros(10,10);
a(10,10) = 10;
Declaring 'a' as zeros and then filling in the index (10,10) could also avoid other errors that option 1 may impose if 'a' is already a variable or function that exists.
Lastly, I think the 2nd option is more readable. Upon first glace of the first option, I'm wondering where 'a' came from.
3 comentarios
madhan ravi
el 15 de Ag. de 2019
Rik
el 15 de Ag. de 2019
There is nothing inherently wrong with the first option, but because it can cause confusion, you should add a comment there. It is also important to make sure that a doesn't exist before this executes.
madhan ravi
el 15 de Ag. de 2019
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