emptying each row of matrix of a in a loop then uses respective matrices produced from it to get a certain value

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I have a matrix, a
a = [1 2;
1 3;
1 5;
1 7;
1 8;];
and this matrix a, is emptied in each row per loop until the last one using this code from Matt J
a0=a;
for i=1:size(a,1)
a=a0;
a(i,:)=[],
end
which result in:
a = [1 3;
1 5;
1 7;
1 8;];
a = [1 2;
1 5;
1 7;
1 8;];
a = [1 2;
1 3;
1 7;
1 8;];
a = [1 2;
1 3;
1 5;
1 8;];
a = [1 2;
1 3;
1 5;
1 7;];
can I create another loop to calculate a certain value, w, from the results from each loop beginning with the orginal until the last one. After each loop answer value, w, is tabulated in matrix b
b = [w
w
w
w
w
w]
there 6 values of w since we consider the orginal a
  4 comentarios
JL
JL el 22 de Ag. de 2019
for i=1:size(a,1)
a=a0;
a(i,:)=[],
% work with matrix a here
end
This code actually works but it doesnt save the values from this loop into another matrix
David Hill
David Hill el 22 de Ag. de 2019
How about,
preallowcating array b = zeros(size(a,1)-1,2,size(a,1));
and having the following in the loop
b(:,:,i)=a;

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Respuesta aceptada

Matt J
Matt J el 22 de Ag. de 2019
Editada: Matt J el 22 de Ag. de 2019
Why not as follows,
b=nan(size(a,1),1); %pre-allocate
for i=1:size(a,1)
tmp=a;
tmp(i,:)=[],
b(i)=max(tmp(:))-min(tmp(:)); %example derived quantity
end
  5 comentarios
David Hill
David Hill el 22 de Ag. de 2019
best to pre-allowcate as Matt discribed. you could b=[]; outside loop and b=[b,w];inside loop. Matt's solution works best.

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