How to obtain variables from a structure inside a for loop?
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Meghana Balasubramanian
el 26 de Ag. de 2019
Comentada: Rik
el 26 de Ag. de 2019
Hello everyone, I have a code to call intensity values which are stored in a structure 's'. The structure 's' has various fields and the field(or variable, I'm not sure what it's called) signal2 has the values I need to access. When I use the following code for just one of the signal2 data's I get the desired output :
Code:
int_val= s.cellList.meshData{1,19}{1,1}.signal2;
int_val(int_val>threshold)=1;
int_val(int_val~=1)=0;
Output:
list of numbers in an excel sheet
({1,19} is a cell inside the field meshData containing the desired values).
However, when I try to create a loop to access each of the cells(1:25),
for j=1:25
int_val= 's_',num2str(i),'.cellList.meshData{1,',num2str(j),'}{1,1}.signal2';
%this ends up creating a character array.
int_val(int_val>threshold)=1;
int_val(int_val~=1)=0;
How do I get the values from the structure?
2 comentarios
Stephen23
el 26 de Ag. de 2019
Your examples are inconsistent: your first example shows a variable named s, then your example
's_',num2str(i),'.cellList.meshData{1,',num2str(j),'}{1,1}.signal2'
shows a variable named s_X for some integer X.: which of these is correct?
Also, why are you converting perfectly good indices into strings?
Meghana Balasubramanian
el 26 de Ag. de 2019
Editada: Stephen23
el 26 de Ag. de 2019
Respuesta aceptada
Bjorn Gustavsson
el 26 de Ag. de 2019
It seems that you read in entire data-sets into a number of numbered struct-variables (presumably s_1, s_2,..., s_25). Dont do that (search for "dynamically generating variable names" or something like that and read the reasons). Instead
read everything into an array of structs. Then you'll have something like this:
s = % Your data-reading-function/script, now returning a struct array
for i1 = numel(s):-1:1
for i2 = size(s(i1).cellList.meshData,1):-1:1
int_val(i1,i2) = s(i1).cellList.meshData{1,i2}{1,1}.signal2;
end
end
int_val(int_val(:)<=threshold) = 0;
int_val(int_val(:)>threshold) = 1;
HTH
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