Value for each loop

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SUSHANT CHAVAN
SUSHANT CHAVAN el 30 de Ag. de 2019
Comentada: Star Strider el 1 de Sept. de 2019
v0=0.01;
y=[0.094 0.15]
for c0=[1 2 5 6]
for c1=[5 6 8 7]
[y,v] = ode45(@(y,v)(([c0]/v^2)-([c1]/v)),y ,v0);
disp(v);
end
end
%%How would I get value of 'v' for each combination of c0 and c1. As there is 16 different combinations of c0 and c1 is possible.
%%How to get value for each combination

Respuesta aceptada

Star Strider
Star Strider el 30 de Ag. de 2019
Your only option is likely to iterate over the vectors in nested loops:
v0=0.01;
y =[0.094 0.15];
yv = linspace(min(y), max(y), 25);
c0=[1 2 5 6];
c1=[5 6 8 7];
for k1 = 1:numel(c0)
for k2 = 1:numel(c1)
[y,v(k1, k2, :)] = ode45(@(y,v)((c0(k1)/v^2)-(c1(k2)/v)),yv ,v0);
% disp(v);
end
end
Plotting them is going to be something of a challenge. This could be an option:
figure
hold all
for k = 1:size(v,3)
surf(c0, c1, v(:,:,k))
end
hold off
grid on
xlabel('c0')
ylabel('c1')
zlabel('zv')
view(-45, 20)
  2 comentarios
SUSHANT CHAVAN
SUSHANT CHAVAN el 1 de Sept. de 2019
Loads of Thanks....
Star Strider
Star Strider el 1 de Sept. de 2019
As always, my pleasure!

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