Forcing matrices to match in size
18 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Let's say I have two single-row matrices A and B.
I want to check if A and B have the same number of columns. If they do, do nothing.
If not, I want to remove the last character in B.
For example, if we have
A = [30 25 78]
B = [17 91 44 83]
Then I want to remove the last column of B, leaving
A = [30 25 78]
B = [17 91 44]
But if we originally had
A = [30 25 78]
B = [17 91 44]
then do nothing. What scheme could accomplish this?
0 comentarios
Respuestas (2)
Arturo Mendoza Quispe
el 8 de Sept. de 2019
B = B(1:numel(A));
This will set B to have the size of A, hence there is no need for an if statement.
3 comentarios
Walter Roberson
el 8 de Sept. de 2019
But you still only want to remove one column of B in that case, right? Because your problem title talks about making them match. Arturo's solution is great to make them match, but is not the correct solution if exactly one column is to be removed from B.
Walter Roberson
el 8 de Sept. de 2019
B = B(1:end-(length(A) ~= length(B)));
Leaves B the same length if A and B are the same length, and otherwise removes exactly 1 element from B.
0 comentarios
Ver también
Categorías
Más información sobre Matrices and Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!