How to add two values to a matrix each five values of that matrix in order to have a new matrix?

Hello everyone,

I have one matrix "A" with dimension 358x1 and I am trying to form a new matrix "B" with dimension 520x1. I need to form the matrix "B" using with the values of "A" where every five values I would like the fifth to be duplicated and attached to itself two times.

More easily, supposing a matrix "XY" with dimension 15x1, I would like to duplicate the rows 5, 10 and 15 two times and then attach that values to themselves. At the end, I should have a new matrix "XYZ" with dimension 21x1. Practically:

XY = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14; 15]

XYZ = [1; 2; 3; 4; 5; 5; 5; 6; 7; 8; 9; 10; 10; 10; 11; 12; 13; 14; 15; 15; 15]

Thank you in advance

Answer 1

[Jackson Burns]

Hi Andrea!

Here's a function I wrote to achieve the goal:

function out = dup5(inputmatrix)
    h=size(inputmatrix,1);
    count = 1; out = zeros(h+floor(h/5)*2,1);
    for i = 1:size(inputmatrix,1)
        if mod(i,5)==0
            out(count:count+2) = [inputmatrix(i); inputmatrix(i); inputmatrix(i)];
            count = count + 3;
        else
            out(count) = inputmatrix(i);
            count = count + 1;
        end
    end

Answer 2

[Bruno Luong]

XY = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14; 15]:

r = ones(size(XY));
r(5:5:end) = 3;
XYZ = repelem(XY,r)

Note if you expand (358 x 1) array you'll get (500 x 1) array.

Answer 3

[madhan ravi]

ix=arrayfun(@(x)[x,x*(ones(~mod(x,5),2))],1:numel(XY),'un',0);
%                multiple of 5----^  ^-- n times
idx=cat(2,ix{:});
XYZ = XY(idx,:)