Create a flashing circle on a plot

I would like to create a flashing circle on a graph.
Any information to go about doing this?

4 comentarios

KALYAN ACHARJYA
KALYAN ACHARJYA el 25 de Sept. de 2019
Have you tried?
Adam Danz
Adam Danz el 2 de Oct. de 2019
@Norman Vyne, you just removed all comments and the question itself. Is that how you thank volunteers in this forum of taking time out of their day to help you?
Matt J
Matt J el 16 de Oct. de 2019
The orginal question was (paraphrased), "How do I put a blinking circle on a plot".
Rena Berman
Rena Berman el 28 de Oct. de 2019
(Answers Dev) Restored edit

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 Respuesta aceptada

Matt J
Matt J el 25 de Sept. de 2019
Something like this is a possibility:
plot(1:5);
hcirc=drawcircle;
while 1
hcirc.Visible='on';
pause(0.2);
hcirc.Visible='off';
pause(0.2);
end

8 comentarios

hcirc=drawcircle;
The code above is undefined
Matt J
Matt J el 2 de Oct. de 2019
Since you Accepted the answer, I assume you figured it out?
Norman Vyne
Norman Vyne el 2 de Oct. de 2019
Actually I am not entirely sure why an error pops up.
Matt J
Matt J el 2 de Oct. de 2019
Editada: Matt J el 2 de Oct. de 2019
The optimal thing would be to upgrade to a version of Matlab which provides drawcircle. If you can't upgrade, you can make your own with patch,
function h=drawcircle(center,radius)
t=0:0.1:360;
x=radius*cosd(t)+center(1);
y=radius*sind(t)+center(2);
h=patch(x,y,'red');
end
Norman Vyne
Norman Vyne el 2 de Oct. de 2019
Not enough input arguments in line 4.
Matt J
Matt J el 2 de Oct. de 2019
You should provide whatever arguments you have omitted in line 4.
Adam Danz
Adam Danz el 2 de Oct. de 2019
Editada: Adam Danz el 2 de Oct. de 2019
Did you enter a "center" containing 2 values and a radius? It's difficult to help you when we don't have any information about what might be causing the problem. What's line 4? What inputs did you provide?
Norman Vyne
Norman Vyne el 2 de Oct. de 2019
I inputted the exact code above and clicked run, then I got an error stating that there is not enough input information in the "x=" part of the function.

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el 28 de Oct. de 2019

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