can any one correct me this code please??
    4 visualizaciones (últimos 30 días)
  
       Mostrar comentarios más antiguos
    
Can you correct me this code to draw the 4 axis (major axe, minor axe and the 2 diagonal and ortogonal axes) not the ellipse
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
    'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
      xbar = s.Centroid(1);
      ybar = s.Centroid(2);
      a = s.MajorAxisLength/2;
      b = s.MinorAxisLength/2;
      theta = pi*s.Orientation/180;
      R = [ cos(theta)   sin(theta)
           -sin(theta)   cos(theta)];
      xy = [a*cosphi; b*sinphi];
      xy = R*xy;
      x = xy(1,:) + xbar;
      y = xy(2,:) + ybar;
      plot(x,y,'r','LineWidth',2);
  hold off
thanks
4 comentarios
Respuestas (4)
  Thomas
      
 el 18 de Sept. de 2012
        
      Editada: Thomas
      
 el 18 de Sept. de 2012
  
      bwlabel works on a 2D matrix, Your 13.jpg image is probably a color (rgb) image and hence is a 3 dimensional matrix. You could convert it to grayscale ( which is a 2d matrix)
bw2 = imread('13.jpg');
% bw2= rgb2gray(bw2);  If image is binary
bw2 = bwlabel(bw2);
imshow(bw2)
s = regionprops(bw2, 'Orientation', 'MajorAxisLength', ...
    'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
        xbar = s.Centroid(1);
        ybar = s.Centroid(2);
        a = s.MajorAxisLength/2;
        b = s.MinorAxisLength/2;
        theta = pi*s.Orientation/180;
        R = [ cos(theta)   sin(theta)
             -sin(theta)   cos(theta)];
        xy = [a*cosphi; b*sinphi];
        xy = R*xy;
        x = xy(1,:) + xbar;
        y = xy(2,:) + ybar;
        plot(x,y,'r','LineWidth',2);
    hold off
 % ADDED EDIT
  plot(s.Centroid(1),s.Centroid(2),'*')
  line(s.Centroid(1)-a:s.Centroid(1)+a,s.Centroid(2));
  line(s.Centroid(1),s.Centroid(2)-b:s.Centroid(2)+b);
4 comentarios
  Image Analyst
      
      
 el 19 de Sept. de 2012
				I think it's because you asked for major and minor axis when what you want does not match regionprops definition of those. See my answer.
  Azzi Abdelmalek
      
      
 el 18 de Sept. de 2012
        
      Editada: Azzi Abdelmalek
      
      
 el 18 de Sept. de 2012
  
      The corrected code
bw = imread('13.jpg');
bw = bwlabel(bw);
imshow(bw)
s = regionprops(bw, 'Orientation', 'MajorAxisLength', ...
  'MinorAxisLength', 'Eccentricity', 'Centroid');
phi = linspace(0,2*pi,50);
cosphi = cos(phi);
sinphi = sin(phi);
xbar = s.Centroid(1);
ybar = s.Centroid(2);
a = s.MajorAxisLength/2;
b = s.MinorAxisLength/2;
theta = pi*s.Orientation/180;
R = [ cos(theta)   sin(theta)  ;-sin(theta)   cos(theta)];
xy = [a*cosphi; b*sinphi];
xy = R*xy;
x = xy(1,:) + xbar;
y = xy(2,:) + ybar;
plot(x,y,'r','LineWidth',2);
hold off
  Pamela Paolo
 el 18 de Sept. de 2012
        2 comentarios
  Image Analyst
      
      
 el 19 de Sept. de 2012
				Pamela, people are giving you what you asked for which I don't think is what you want. See my answer.
  Image Analyst
      
      
 el 19 de Sept. de 2012
        
      Editada: Image Analyst
      
      
 el 19 de Sept. de 2012
  
      Pamela, My guess is that you really mean Feret Diameter ( http://www.sympatec.com/Science/Characterisation/05_ParticleShape.html) rather than the major and minor axis of an ellipse fitted to the shape. Am I correct? Feret diameter will touch at least two points on the perimeter of the object, like a caliper distance, while an ellipse's axes won't necessarily have the axis endpoints on the shape's perimeter.
MATLAB does not provide Feret diameters. You can calculate it yourself using bwboundaries. Let me know if you can't figure it out. I don't have any code all ready to give you though. However, you might take a look at this File Exchange submission:  http://www.mathworks.com/matlabcentral/fileexchange/30402-feret-diameter-and-oriented-box
6 comentarios
  Image Analyst
      
      
 el 19 de Sept. de 2012
				PCA would probably be good. I don't have any PCA code to share with you, sorry.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!



