Finding bit's postions in cell

I have a binary number in a cell. I want to find 1's bit positon in cell. Can anyone help me out here.

val =

'0000000000000000'

'0000000000000010'

'0000000000000011'

'0000000000000111'

'0000000000001000'

'0000000000011010'

'0000000000100000'

'0000000000100001'

'0000000000100010'

'0000000000110100'

'0000000001001100'

'0000000001010101'

'0000000001011001'

'0000001010011010'

'0000001010110010'

'0000001010110110'

'0000001011001100'

'0000001100000110'

'0000001100100000'

'0000001100111100'

'0000001101010100'

'0000001101110010'

'0000001110111011'

'0000001111011011'

'0000001111100000'

'0000010000000000'

'0000010000001000'

Thanks & Regards

Answer 1

[Adam Danz]

The data in your question contains what appears to be a cell array of strings (or character arrays) where each string represents a binary number. If your question is how to find the position of each 1 within each string,

onePos = cellfun(@(s)strfind(s,'1'), val, 'UniformOutput', false); 

This will produce a cell array of indices. onePos{n} lists the positions of '1's within the nth string of 'val'.

For example, the first row has no 1s so that cell element is empty

onePos{1}
ans =
     []

The 6th row has 1s in the 12th, 13th, and 15th character

onePos{6}
ans =
    12    13    15