Find and count how many capital characters are in str, and then change them to lower cases USING LOOPS

how to do this with loops i know the regular way but i want to know with loops

please if you can help then do

but dont comment if you will just make random comments and not help

please

thank you

Answer 1

[Daniel M]

s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'
[caps,inds] = regexp(s,'[A-Z]','match');
numCaps = length(inds);
for n = 1:numCaps
  s(inds(n)) = lower(caps{n});
end

Answer 2

[Rik]

You can easily do this without loops:

s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'
s_out=lower(s);
N_upper_case=sum(s~=s_out);

If for some strange reason you insist on doing this with loops, you can easily add some indexing:

s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'

s_out=s;
N_upper_case=0;
for n=1:numel(s)
    s_out(n)=lower(s_out(n));
    N_upper_case=N_upper_case+double(s_out(n)~=s(n));
end

If you ask me the second option is much more complex (and slower) than the first, without getting any benefits.

Answer 3

[Steven Lord]

The isstrprop function can help you identify which characters are upper-case, which are lower-case, and which are neither. After that, your loop simply needs to see if the current letter is a different case than the next letter. Since I suspect this is a homework assignment I'm not going to give you the implementation; you should be able to complete it given these hints. If you can't, show us what you've written and ask a specific question about where you're having difficulty and we may be able to provide you with additional guidance.