how to replace the element with random number based if statement
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Genz
el 16 de Oct. de 2019
Comentada: sid Chen
el 17 de Oct. de 2019
Helllo everyone
i have a problem to change element of array with iteration approach. refer to https://www.mathworks.com/matlabcentral/answers/8817-how-to-replace-the-elements-of-a-matrix-using-the-conditions-if-else , i have same problem but little different. for instance i have mut1 = [.11 .12 .13 .14 .15 .16 .17 .18 .19 .20] and constan number 0.5. i want to replace element of mut1 with 'random number between' if random number(rmi) < 0.5. so this is what iam doing.
mutC = zeros(size(mut1));
pm = 0.5;
for i = 1:numel(mut1)
rmi = rand(1,1)
rCm = rbC+(raC-rbC).*rand(1,1)
if rmi<pm
mutC = rCm
else
mutC = mut1
end
end
but the final result is always mutC = mut1. there is no number from rCm.
I will appreciate any help. thank you.
0 comentarios
Respuesta aceptada
Andrei Bobrov
el 16 de Oct. de 2019
Editada: Andrei Bobrov
el 16 de Oct. de 2019
mutC = mut1;
[m,n] = size(mut1);
pm = 0.5;
rmi = rand(m,n);
rCm = rbC+(raC-rbC).*rand(m,n);
for i = 1:numel(mut1)
if rmi(i) < pm
mutC(i) = rCm(i);
end
end
or
pm = .5;
mutC = mut1;
[m,n] = size(mut1);
rCm = rbC+(raC-rbC).*rand(m,n);
lo = rand(m,n) < pm;
mutC(lo) = rCm(lo);
3 comentarios
Más respuestas (1)
sid Chen
el 16 de Oct. de 2019
Andrei Answer is very clear.
The problem is
if rmi<pm
mutC = rCm
else
mutC = mut1
with these code, you replace the whole matrix, all the elements are replaced.
To avoid this, you need to replace only one elements step by step. Just add an subscipt 'i' to point the element to be repalced.
if rmi<pm
mutC(i) = rCm(i)
else
mutC(i) = mut1(i)
2 comentarios
sid Chen
el 17 de Oct. de 2019
if rmi<pm
mutC(i) = rCm % change here, rCm is a number,not a matrix
else
mutC(i) = mut1(i)
Ver también
Categorías
Más información sobre Function Creation en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!