Why do my axis change dimensioins?
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Dawid Brits
el 19 de Oct. de 2019
Comentada: Dawid Brits
el 19 de Oct. de 2019
Hi All, this code is supposed to plot a 3D surface and a contour plot of the function with wells at (-2, 2) and (3, -1). However, when I run the code, firstly, the wells are not in the right places, and the dimensions of the axis change as my inputs for x and y change (ie the position of the wells change). What am I doing wrong?
Here is my code,
function M = landscape(x, y)
M = H1(x, y) + H2(x, y);
function h1 = H1(x, y)
R1 = 2;
s1 = [-2;2];
n1 = 2;
h1 = (1./(1+(R1./sqrt((x-s1(1)).^2+(y(:)-s1(2)).^2)).^n1));
end
function h2 = H2(x, y)
R2 = 1;
s2 = [3;-1];
n2 = 1;
h2 = (1./(1+(R2./sqrt((x-s2(1)).^2+(y(:)-s2(2)).^2)).^n2));
end
subplot(1, 2, 1)
surf(M)
subplot(1, 2, 2)
contour(M)
end
And two different graphs the first with x and y -5:5 and the second with x and y -10:10
![landscape55.jpg](https://www.mathworks.com/matlabcentral/answers/uploaded_files/243475/landscape55.jpeg)
![landscape1010.jpg](https://www.mathworks.com/matlabcentral/answers/uploaded_files/243476/landscape1010.jpeg)
Notice how the position of the wells change?
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Respuesta aceptada
Steven Lord
el 19 de Oct. de 2019
What happens, according to the documentation, when you call surf with one input argument? What does surf use for the X and Y coordinates at which to place the points that make up the surface?
Try calling surf with three input arguments instead.
The same applies to the contour function. You called it with one input when you should be calling it with three.
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