Varargout - How to realize function call

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Dario Walter
Dario Walter el 21 de Oct. de 2019
Respondida: Dario Walter el 1 de Nov. de 2019
Hey guys,
let us assume the following function:
function [out1,out2,out3]=test(j,k)
out1= nargin;
out2 = j-k;
if out2 == 10
out3 = 5;
end
end
The function call [val1,val2,val3] = test(10,11) returns an error because c is obviously undefined. How do I make this code run so that out3 is returned when it exists?
Thanks for your help!
  1 comentario
Guillaume
Guillaume el 21 de Oct. de 2019
The function call [val1,val2,val3] = test(10,11)
will always require 3 outputs from the function, so test must always return at least 3 outputs for that call to be valid.
That's independent of whether or not the function only returns some outputs under some conditions.

Iniciar sesión para comentar.

Respuesta aceptada

Stephen23
Stephen23 el 21 de Oct. de 2019
Simpler:
function [out1,out2,out3]=test(j,k)
out1= nargin;
out2 = j-k;
out3 = [];
...
if out2 == 10
out3 = 5;
end
end

Más respuestas (2)

per isakson
per isakson el 21 de Oct. de 2019
Editada: per isakson el 21 de Oct. de 2019
varargout exercise. Try something like this
function varargout = test( j, k )
out1= nargin;
out2 = j-k;
if out2 == 10
out3 = 5;
end
if exist( 'out3', 'var' ) == 1
varargout = { out1, out2, out3 };
else
varargout = { out1, out2, [] };
end
end
or
function varargout = test( j, k )
out1= nargin;
out2 = j-k;
if out2 == 10
out3 = 5;
else
out3 = [];
end
varargout = { out1, out2, out3 };
end

Dario Walter
Dario Walter el 1 de Nov. de 2019
Thanks yor your help folks! I thought that a more sophisticated way exists than setting out = [ ]. Anyway, I am happy with that :)

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