Dice rolling & loops

Hi! Im currently solving a task in which i have to simulate dice rolling. I'm supposed to generate 10 random numbers (between 1 and 6 of course, that part I've managed to do using a=rand(1,10) and then multiplying with 6 and rounding them). The next part is writing a loop which I'm struggling with. If 5 or 6 is gotten 7 or more times its supposed to display 'gain is 2',if 5 or 6 is gotten 4,5 or 6 times then display gain is 1 and if its gotten 4 or less times then gain is 0. Any help or advice is appreciated

Answer 1

[James Tursa]

The loop could look something like this:

n = numel(a);
got5or6 = 0;
for k=1:n
    if( _______ ) % you fill in the blank here
        got5or6 = got5or6 + 1;
    end
end
% you put code here to test got5or6 value and print appropriate message

You need to write code for the two places indicated above. For the if-test, the code would test to see if a(k) is equal to 5 or equal to 6. For the display part, you will write code to see which range the got5or6 value fits into and then print the appropriate message. Give this a try and then ask for more help if you need it.

Answer 2

[Jon]

You can generate a vector with 10 dice rolls using

rolls = randi(6,1,10)

You can determine how many of the 10 rolls are either a 5 or 6 using

count = sum(rolls>=5)

I think with those ideas you could then setup your logic to branch and display the corresponing text.

[Nina Helena]

First of all,thank you so much for taking the time out of your day to answer me!

Secondly, something along those lines and using if and elseif was my original idea but my professor said that i can only use for loop which,in all honesty, i'm struggling to incorporate in this task.

If you or anyone else has any ideas it'd be appreciated

Thank you

[Jon]

You could do the whole thing with no loops and no if statements with something like this:

gain = [0 0 0 1 1 1 2 2 2 2]
rolls = randi(6,1,10)
count = sum(rolls>=5)
disp(['gain is ',num2str(gain(count))])