if statement in for loop with cell arrays
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I have this problem with matlab, I have to assign letter grades to the scores I have, but I couldn't do it. Can anybody help?
s.name={'Seda','Ayça','Deniz','Kerem','Mete'}
s.score={'90','45','68','86','82'}
N=lenght(s.score)
for i = 1:1:N
if (i)<100 & (i)>=90
grades(i)='A'
elseif (i)<90 & (i)>=80
grades(i) ='B'
elseif (i)<80 & (i)>=70
grades ='C'
elseif (i)<70 & (i)>=60
grades ='D'
else
grades = 'F'
end
end
5 comentarios
Guillaume
el 30 de Oct. de 2019
Editada: Guillaume
el 30 de Oct. de 2019
Can you have char varaible as values in discretize?
Yes,
>> score = [90, 45, 68, 86, 82];
>> discretize(score, [0 60 70 80 90 100], {'F', 'D', 'C', 'B', 'A'})
ans =
1×5 cell array
{'A'} {'F'} {'D'} {'B'} {'B'}
All discretize does is index the values array with the indices it would normally return. You can have pretty much anything that can be indexed as values.
Respuestas (1)
Fabio Freschi
el 29 de Oct. de 2019
To stick with the OP snippet
- I added semicolons all over the place
- I changed the variable type in s.score to doubles
- I preallocated the grades variable as string array
- I changed the check on (i) with s.score{i}
- I added <= 100 to include also the possibility of 100 score
- I changed the single & to double && for logical scalar values
s.name={'Seda','Ayça','Deniz','Kerem','Mete'};
s.score={90,45,68,86,82};
N=length(s.score);
grades = strings(N,1);
for i = 1:1:N
if s.score{i}<=100 && s.score{i}>=90
grades(i)='A';
elseif s.score{i}<90 && s.score{i}>=80
grades(i) ='B';
elseif s.score{i}<80 && s.score{i}>=70
grades(i) ='C';
elseif s.score{i}<70 && s.score{i}>=60
grades(i) ='D';
else
grades(i) = 'F';
end
end
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