How to perform right circular shift

Hi. I have written a code to perform circular shift but it does not give me all X28 and Y28 keys . It returns only one X28 and Y28 with out any circular shift.What I did wrong

key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
icount=0;
for i=1:16
    icount=icount+R_key(i);
    I=icount;
end

%circular shift
X28 = circshift(x', -icount)';
Y28 = circshift(y', -icount)';

[Shubham Gupta]

what was the output that you were expecting?

[Walter Roberson]

sum(R_key) is 28, so icount is 28. That is the same as the length of your data, so you are circular shifting each bit of data exactly to the same place it started.

[sadiqa ilyas]

Yes but I want all these outputs. 16 out puts after the circular shift performed according to R_key

Answer 1

[Walter Roberson]

key_56=1:56;
x=key_56(1:28);
y=key_56(29:56);
R_key=[1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1];
shift_counts = cumsum(R_key);
num_shifts = length(shift_counts);
x_shifted = zeros(num_shifts, length(x));
y_shifted = zeros(num_shifts, length(y));
for i = 1 : num_shifts
    x_shifted(i, :) = circshift(x, -shift_counts(i));
    y_shifted(i, :) = circshift(y, -shift_counts(i));
end

[sadiqa ilyas]

Thanks