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Creating random vector with 10 different lengths

Asked by Chelles Rees on 10 Nov 2019 at 21:13
Latest activity Commented on by Chelles Rees on 10 Nov 2019 at 23:46
I can't seem to ceate a random vector from 1-10k then 1-20k then 1-30k consectuively until 100k logging different values.
Here is the code I have so far:
inc=[10000 20000 30000 40000 50000 60000 70000 80000 90000 100000];
for l=1:length(inc) %creating a loop to go through the 10 values of inc
vec1 = randi(1,inc(l)); %geenrating random vector from 1-respective value of inc
Any help would be appreciated

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2 Answers

Answer by Image Analyst
on 10 Nov 2019 at 23:12
 Accepted Answer

You need to tell it either one row or one column. Try this:
inc = [10000, 20000 30000, 40000, 50000, 60000, 70000, 80000, 90000, 100000];
maxValue = 100000; % Whatever you want the potential max value in the vector to be.
for k = 1 : length(inc) % Creating a loop to go through the 10 values of inc
% Generating random vector from 1-respective value of inc.
vec1 = randi(maxValue, 1, inc(k)); % or randi(maxValue, inc(k), 1);
fprintf('Made a vector with %d rows and %d columns.\n', size(vec1, 1), size(vec1, 2));
end

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Thank you!

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Answer by per isakson
on 10 Nov 2019 at 21:49

Documentation on randi says:
X = randi(imax,n) returns an n-by-n matrix of pseudorandom integers drawn from the discrete uniform distribution on the interval [1,imax].
Thus, randi(1,inc(l)); will return a matrix of ones the same as ones(inc(l)).
vec1 is overwritten in each iteration of the loop. Is its value stored in another variable?

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