check my code please

clc,close all,clear all
codn=100;
%  fc=6e+3;
fs=360;
bode=10;
code=round(rand(1,codn));
code_len=round(1/bode/(1/fs))
 for ii=1:codn   
     x((ii-1)*code_len+1:code_len*ii)=code(ii)
 end
 
 x2 = x-(1/2)    % get rid of most of the dc peak
 
% set up time and frequency arrays 
length(x)
 u = length(x)
 N = 2^nextpow2(u)
 
delt = 1/fs;
delf = fs/N;
figure(1)
tvec2=(1:length(x2))*delt;
plot(tvec2,x2(1,:)+0.5)
title('orignal baseband')
 xlabel('time');
 ylabel('amplitude')
ylim([-1 1.5]);
 y = fftshift(fft(x2)/N);   
z=abs(y);
figure(2)
fvec2=(-length(x2)/2:length(x2)/2-1)*delf;
plot(fvec2,z)
title('FFT')
xlabel('frequency')
 ylabel('amplitude')
 figure(3)
 z=y;
 z(abs(fvec2)>50 & abs(fvec2)<=150)=0
 plot(fvec2,abs(z))
 xlabel('frequency removed from 50 to 150 HZ');
 ylabel('amplitude')
 figure(4)
zf=fftshift(z)*N;
zifft=ifft(zf)+0.5;
plot(tvec2,abs(zifft))
ylim([-1 1.5])
title('recovered signal')
xlabel('time');
 ylabel('amplitude')

I have make correction in my code.Can anyone tell me that my code is now right?,but i have doubt on my fvec2 is it right?.Moreover i have calculated my data rate please check it whether it is right or wrong.

PARAMETERS FOR DATA RATE ARE;

T=10ms

F(signal frequency)=1/T=0.1KHZ

Fs(sampling frequency)=360HZ

bode=10

No.of bits in 1ms=10 bits

No.of bits in 1s=10k bits/sec

data rate will be=10kb/sec

[Walter Roberson]

Can anyone tell me that my code is now right?

No, at the moment you are the only person who is able to do that. At the moment, the purpose of your code is unknown, undocumented, so we could either say "The correct result is defined by whatever the code does because there is no way to contradict that", or we could say "An undocumented program is always incorrect."

Answer 1

[imran khan]

purpose of my code is that i have generated OOK signal and then i have taken FFT of signal and remove frequency from 50-150HZ.after removing frequency i see signal in time domain by taking IFFT.In ifft signal should be close to our original OOK signal in figure(1) so that i can transmitt it.