How Can i write a function that takes a structure array and returns this array with bubble sorting
Mostrar comentarios más antiguos
I want to write a function that takes a structure array holding information about students(name,age,gpa etc.) and returns this array by ordering the students with respect to their age by bubble sort.
function a=structarray (age,a)
for i=1:length(a)-1
if a(i).(age)>a(i+1).(age)
T=a(i);
a(i)=a(i+1);
a(i+1)=T;
i write this. but of course it is not working.pls guys help me.
4 comentarios
Walter Roberson
el 26 de Nov. de 2019
What inputs would be typical for the age parameter ?
By the way:
a([i, i+1]) = a([i+1,i]);
exchanges without needing any temporary variable.
Dart Min
el 26 de Nov. de 2019
Walter Roberson
el 26 de Nov. de 2019
When you call the function, passing in that a as the second parameter, what would you pass in as the first parameter?
What difficulties are you observing with your code?
Dart Min
el 26 de Nov. de 2019
Respuesta aceptada
Más respuestas (1)
Stijn Haenen
el 26 de Nov. de 2019
Maybe this will work:
ages=[structurearray.age];
[a,b]=sort(ages);
newstructurearray=structurearray(b);
The used structure is attached.
3 comentarios
Walter Roberson
el 26 de Nov. de 2019
sort() is not a bubble sort.
Stijn Haenen
el 26 de Nov. de 2019
Ah i missed that,
maybe this:
a(1).name='Matt';
a(1).age=22;
a(1).gpa=77;
a(2).name='Chris';
a(2).age=23;
a(2).gpa=45;
a(3).name='Park';
a(3).age=26;
a(3).gpa=81;
a(4).name='Stewie';
a(4).age=19;
a(4).gpa=44;
ages=[a.age];
[b]=unique(ages);
new_a=[];
for i=1:numel(b)
num=(ages==b(i));
new_a=[new_a;a(num)];
end
Walter Roberson
el 27 de Nov. de 2019
That just pushes the sorting off into unique() but the assignment requirement is to use bubble sort.
Categorías
Más información sobre Multidimensional Arrays en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!