Calculating median along specific dimension of 3D array

4 visualizaciones (últimos 30 días)
Uerm
Uerm el 27 de Nov. de 2019
Comentada: Uerm el 28 de Nov. de 2019
Hi,
I have a 3D array (S) of size 75x31253x1523. If I was to calculate the median along the second axis (for each row) it would be median(S,2) which would result in a 75x1x1523 array.
However, because the array is large, I run out of memory when I try to calculate the median of the whole array with one line. Therefore, I want to calculate the median in chunks. The problem is that each chunk will be of size Ax1xB. When stacking them together, they will be of size AxNxB. How can I calculate it in chunks and still end with size Ax1xB (75x1x1523)?
Thanks!
  2 comentarios
Stephen23
Stephen23 el 27 de Nov. de 2019
Check your available memory, it works when I tried it (32 bit R2012b):
>> S = randi(75,31253,1523);
>> M = median(S,2);
>>
You might be able to increase your swap space, which although slow can be effective in avoiding such errors.
Uerm
Uerm el 27 de Nov. de 2019
Sorry, I wrote the dimensions wrong. They are 90x38021x1633. However, they are from other calculations and take up approximately 22.5 gb of space.
Can I increase the swap space when I use a mac?

Iniciar sesión para comentar.

Respuesta aceptada

Matt J
Matt J el 28 de Nov. de 2019
Editada: Matt J el 28 de Nov. de 2019
M=nan(90,1,1633);
for i=1:90
M(i,:,:)=median(S(i,:,:),2);
end

Más respuestas (0)

Categorías

Más información sobre Logical en Help Center y File Exchange.

Productos


Versión

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by