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# How to divide column vector elements in unequal parts against a condition?

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Atique Barudgar on 28 Nov 2019
Commented: Atique Barudgar on 28 Nov 2019
I have Pressure data against 5 days(for sample)
I want Pressure for all these days in different column according to days in single matrix only?
I want code which does everything, because I have big data.
Thanks
I want all column of pressure for different days inside one matrix or variable say i.e x or y.
Is it possible because length of all pressure data for a day will be different from each other?
File attached

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### Accepted Answer

Stephan on 28 Nov 2019
Edited: Stephan on 28 Nov 2019
Due to different lengths of your daily data you should use a cell array:
A = readmatrix('New Text Document.txt');
k_min = min(unique(A(:,1)));
k_max = max(unique(A(:,1)));
x = cell(1,k_max-k_min+1);
for k = k_min:k_max
x{:,k} = A(A(:,1)==k,2);
end
Access the data of the single days by using:
x{1,2} % to look day 2
x{1,5} % day 5

#### 2 Comments

Atique Barudgar on 28 Nov 2019
Thank you very much
Atique Barudgar on 28 Nov 2019
If anybody have another method, please share.

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