How to extract sub-matrices from a big matrix?
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    Mohamed Nedal
 el 21 de Dic. de 2019
  
Hello everyone, 
I have two matrices, kindly find the attached file 
soho ---> size = 23×12 , each row represents an event. 
omni ---> size = 8760 × 17 , each row represent an hour (timeseries data). 
The first three columns are, in order, "year", "month", "day". 
I need to do the following operation: 
if soho_day = omni_day 
    take that omni_day and the following 120 rows (hours) and put them as a separate matrix with a prefix (i.e., omniSUB_1). 
    and so on 
I have these code blocks 
% to find the matched date and store the that day along with the following 5 days (120 hours) in another matrix. 
for n = 1:length(soho) 
    for m = 1:length(omni) 
        if datetime(soho(n,1),soho(n,2),soho(n,3),...
                'Format','dd/MM/yyyy') == ...
                datetime(omni(m,1),omni(m,2),omni(m,3),...
                Format','dd/MM/yyyy') 
            for k = m:120 
                omniSUB{n,:} = omni(k,:); 
            end 
        end
    end 
end 
and 
% to create sub-matrices. 
Prefix = 'omniSUB_'; 
for i = 1:Month_length 
    var_name = strcat(Prefix, num2str(i)); 
    data_child = genvarname(var_name); 
    eval([data_child ' = omniSUB{i}']); 
end 
but I don't know how to put them together to do that operation. Please correct me. 
I appreciate your help. 
Thanks in advance 
4 comentarios
  Stephen23
      
      
 el 22 de Dic. de 2019
				
      Editada: Stephen23
      
      
 el 22 de Dic. de 2019
  
			"That's why I need to separate each 5-day period in a separate matrix because I have another function that will loop over these matrices and do further analysis for each one."
Exactly as I wrote in my earlier comment, you just need to use indexing.
You can easily store the separated data in one array (e.g. a cell array) using basic MATLAB indexing, which will be much simpler and more efficient than what you are doing now, and then it is trivial to "loop over these matrices and do further analysis for each one" as you wrote. So far nothing you have shown or described requires your complex and inefficeint approach of accessing variable names dynamically.
Respuesta aceptada
  Ridwan Alam
      
 el 21 de Dic. de 2019
        
      Editada: Ridwan Alam
      
 el 21 de Dic. de 2019
  
      % to find the matched date and store the that day along with the following 5 days (120 hours) in another matrix. 
for n = 1:size(soho,1) 
    omniRowInd = find(omni(:,1)==soho(n,1) & omni(:,2)==soho(n,2) & omni(:,3)==soho(n,3),1,'first');
    if ~isempty(omniRowInd)
        tempTable = omni(omniRowInd:min(omniRowInd+119,size(omni,1)),:);
        eval(['omniSUB_' num2str(n) '=' 'tempTable;']);
    end
end
Hope this helps!
10 comentarios
  Stephen23
      
      
 el 23 de Dic. de 2019
				
      Editada: Stephen23
      
      
 el 23 de Dic. de 2019
  
			"Could you determine the problem here plz? "
Are you checking all of the cells of the cell array, not just the last one?:
find(~cellfun(@isempty,C))
It is quite possible that the if condition is never true. You can check this by printing it in the loop, or collect it into a vector and checking it after the loop:
N = size(soho,1); 
C = cell(1,N);
L = false(1,N); % logical vector
for k = 1:N 
    omniRowInd = find(omni(:,1)==soho(k,1) & omni(:,2)==soho(k,2) & omni(:,3)==soho(k,3),1,'first'); 
    if ~isempty(omniRowInd)
        L(k) = true; % if the condition is true
        C{k} = omni(omniRowInd:min(omniRowInd+119,end),:); 
    end 
end
% Check on which iteration/s the conditions was true:
any(L)
find(L)
Note how easy it is using indexing to access the new variable L. Trying to use eval to do something similar with lots of numbered variables would be much more complex.
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