# conversion from binary to decimal

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Eli on 2 Jan 2020
Commented: Walter Roberson on 2 Jan 2020
disp('conversion from binary to decimal');
z=input('give a floating point number ','s');
n=strfind(z,'.'); %index of the .
z1=z(1:n-1); %z1 vector
disp(z1);
z2=z(n+1:length(z)); %z2 second part after .
x=bin2dec(z1); %bin 2 dec transformation of the first part of the number (before .)
%transformation of the decimal part of the number
b=0.5;
y=0;
for i=1:length(z2)
y=y+(z2(i)-48)*b; %what is -48, it is set for precsion?
b=0.5*b;
end
fprintf('Il numero in base 10 e'':\n');
-48 is set for a better precision in the conversion from binary to decimal or there is another reason?
Thank you!!

David Hill on 2 Jan 2020
No, the -48 is converting the ascii character '0' or '1' to a number.
##### 2 CommentsShowHide 1 older comment
Walter Roberson on 2 Jan 2020
In all character sets that I have been able to find since the 1930's, IBM's EBCDIC is the only one that did not encode the characters '0' through '9' as consecutive positions in the table with '0' being the low value (EBCDIC coded '1' as the low value and '0' followed '9' if my memory is correct)
Therefore for all computer languages that you are ever likely to encounter, you can rely on the fact that the character code for a particular single digit "Arabic numeral" is that many positions after the position for the character code for '0'.

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